Maths - magic with binary numbers

July 30, 2018 Chandrashekhar

Hey you :) get ready for binary magic,

I have written a C program that will tell you the number which u r thinking of.

Just go through this C program.

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#include<stdio.h>
#include<conio.h>

main()
{
char ans;
int i,arr[5],number=0;

clrscr();

printf("THINK OF ANY NUMBER BETWEEN 1 AND 31 INCLUSIVE!\n\n");

//Take inputs from user.

    for(i=0;i<5;i++)
    {
         printf("FIRST ROW : 3 1 5 7   9 11 13 15 17 19 21 23 25 27 29 31");
         printf("\nSECOND ROW : 6 3 2 7 10 11 14 15 18 19 22 23 26 27 30 31");
         printf("\nTHIRD ROW : 4 5 6 7 15 13 14 12 20 21 22 23 28 29 30 31");
         printf("\nFOURTH ROW : 8 9 10 11   12 13 14 15 24 25 26 27 28 29 30 31");
         printf("\nFIFTH ROW : 31 17 18 19 20 21 22 23 26 25 24 27 28 29 30 16");

printf("\n\nJUST KEEP THINKING AND TELL, IS THE NUMBER PRESENT IN THE ROW %d ? (Y/N) :", (i+1));

fflush(stdin);
scanf("%c",&ans);

         if((ans=='y')||(ans=='Y'))
             arr[i]=1; // store 1 for ans:Y ()
         else
             arr[i]=0; // store 0 for ans:n (No) or char other than Y/y

clrscr();
}

     for(i=0;i<5;i++)
     {
          number=number+(arr[i]*power(i));
     }

printf("\n\nGET READY FOR ANSWER! CLOSE YOUR EYES FOR FIVE SECONDS ... ");

delay(2000); // Wait for two seconds

// countdown ;) for answer

     for(i=5;i>0;i--)
     {
           printf("%d\b",i);
           delay(1000); //Wait for 1 second.
     }

clrscr();

printf("\n\nNUMBER YOU ARE THINKING OF IS : %d = ;-) ",number);

getch();
return(0);
}

// function that returns 2 raised to 'n' (powof2 in this case)

int power(int powof2)
{

int j,a=1;